PropertyName: Defines the name of the property of the object type that represents each row within the grid.It points to a field in the items from the ItemsSource collection of the Picker. ItemDisplayBindingPath (string): Sets the display path of the items in the Picker selector.ItemsSourcePath (string): This property is used to specify a property of your data class to be used as source for the Picker control.
The DataGridPickerColumn uses a Picker control in Edit mode to select a value from list of possibilities. Then use x:Bind to bind the ComboBox.Download free 30-day trial DataGrid PickerColumn Your view model should have a property SelectedBlockName. You typically bind this ComboBox.SelectedValue to the same view model (data context) that exposes the source collection, in your case the BlockDetails collection. Both properties serve the same purpose of exposing the currently selected item. You use ComboBox.SelectedValue instead of ComboBox.SelectedItem, if you are not interested of the actual data item, but a specific value of this item. You have ComboBox.DisplayMemberPath to select the property of this data type, which should be displayed by the ComboBox in the drop down.įinally you have ComboBox.SelectedValuePath to select a property of this data type to be the ComboBox.SelectedValue. You have an object or data type that is an item of the ComboBox. I think you either confused the SelectedValue property or missed to post some details. In my model the class is declared as follows, public class VmServiceMethodBlockDefinition : BindableBaseThreadSafe
But the problem is it doesn't select/display the item. When I expand the combobox I can see the items inside it. I have a combobox which is bound to a property called "BlockDetails" in the viewmodel.
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